What we got here is a dilemma

Again, this is wrong.

 

The fact that you are intentionally posting bad information only makes you look like an idiot. I don't know what you hope to gain out of this other than everyone else watching you act like a child. Stop.

 

Where's the dislike button?

 

I would love to hear you explain this to my thermodynamics professor...........
Now there is one condition your argument may have validity. In the case you have thermostat where your main air entering the stove is being controlled to maintain a set stove temperature. In that condition as you cool the stove it would most likely open the primary to bring the stove temperature back up until it reaches an equilibrium causing more wood to be burned. However in the case of a fixed air setting on a wood stove it is impossible for that phenomena to occur. The only thing that happens is you will lower the outside temperature causing a larger Delta T and in increasing the amount of heat transfer between the inside and outside of the stove. The larger the Delta T the more heat you are able to pass between the two temperature zones but even then you are limited to an extent by a materials thermal conductivity

 

If you don't understand something, don't try to discount it as "intentional bad information". I'm educating people. This is a hard thing to understand and grasp, which is why many don't agree. Just like the old trick: HOT water will freeze faster than Cold water. I've won 100's of $'s on that bet, and it is based on the exact same premise because of a larger Delta T.

The larger Delta T you are referring to is exactly why you will burn more wood. With the same amount of fuel (wood) and oxygen, there will be a different coefficient. Keep in mind, this is NOT always a BAD thing. If you need more heat quicker, this is a good thing. Which is why some report "It works better with the blower for me...". That is fine. In my case I don't need more heat, I prefer a longer burn time. I also prefer not to hear a blower run, I don't care how "quiet" they are, they are ALL noisy.

Think about it this way, this is an easy way to understand it. I think we can all agree with set load of wood and air, you get a set amount of BTU's out of it. Ok, so now you turn on the blower, and get more heat off the stove right? Those are BTU's, well guess what, that means you will burn more wood, those "added BTU's" are not created with the magic of a "blower'.

 

I understand it perfectly. You are wrong. I get longer burn times from the stove with the blower than without since the blower allows you to move the heat better at lower temps. So, again, you are wrong and you should take a moment to realize you are acting an azz.

 

1. This has nothing to do with quick heat and everything to do with exchanging cold air for warm air to be able to heat a larger area longer.
2. I get longer burns with the blower.
3. You have never used a blower.

 

And you absolutely are pushing bad information with your idiotic "say no to blowers" repetitive crap.

Also, in your clownishness, you have never give any numbers to support your opinion.

 

The reason a blower can be effective is that it is taking some of the BTU's that would otherwise be "wasted" in the vicinity of an already-hot stove and helping to move them away from the stove. It's not creating BTU's, just using the ones that are already being created more effectively.

Here's a website that explains the Mpemba effect: http://math.ucr.edu/home/baez/physics/General/hot_water.html

Got anything that explains why a blower moving air outside the stove would cause combustion inside the stove to occur more rapidly? Is there a law of physics or thermodynamics that says cooling the outside of a chamber where combustion is occuring will cause the combustion inside to occur more rapidly?

 

LOL! And YOUR numbers are? I just explained it in plain English. It has nothing to do with moving cold air and warm air. You are moving air, over a hot surface to remove heat from it. So in fact, you are heating air, and then moving it.

And PS- I use 4 (FOUR, count them, 1, 2, 3, 4) blowers for your information. And I hate all 4 of them!

 

Yes, the same amount of BTUs are created. With the blower, you get them into the room. Without the blower, they go up the stack.

 

There is some truth to that, but that is not all that is going on. Blowing across the hot surface of the stove (removing heat) is much different than just blowing air around the rooms (as I do).

 

Think about it this way, this is an easy way to understand it. I think we can all agree with set load of wood and air, you get a set amount of BTU's out of it. Ok, so now you turn on the blower, and get more heat off the stove right? Those are BTU's, well guess what, that means you will burn more wood, those "added BTU's" are not created with the magic of a "blower'.

ok, here's the inaccuracy in this statement.
BTU's are what they are, energy expressed as heat. the fuel being burned contains a certain amount of "potential energy" which is released as the fuel is burned of this a percentage of this energy is transferred to the hull of the stove and the rest is carried out through the flue system.
now, the delta t refers to the differential temperature between the surface of the hull of the stove and the air surrounding it, the energy is transferred based on the degree of the delta t. the higher the differential temperature , the faster the cooler particles syphon energy off the hotter particles until the delta is equalized (which doesnt happen until the stove cools to rom temperature after the fire has gone out.

energy cannot be destroyed , only dissipated, so the pushing of air across the top of the stove in order to "convect" heat away from the stove simply does not create any difference in the amount of energy being released by the fire though it does allow more energy to be dissipated into the air by keeping the delta t at a relative range for a longer period of time. you do NOT "get more heat off the stove" per se, you allow it to be convected away from the stove creating a larger envelope of heated air. as this heat is conducted through the steel to the air to be either "radiated" or "convected" away it is still the same "potential" unless the fuel air mixture is adjusted. the difference between running with or without a blower is that if there is no air movement for convection then as the air which is not being convected away from the stove will warm more in close proximity to the stove so the delta t will decrease thus the stove hull will stay warmer as the energy is being absorbed to the much warmer air at a slower pace.

none of this will have any noticible effect on the speed of energy release from the fuel

 

So you use blowers but tell people to say no to them.

 

Mike, that is all just fine. But what your forgetting is the OTHER Delta T, and this is the tricky part. That is the difference of the temperature between the firebox (the air in it, the wood in it, the bricks....) and the outside of the hull of the stove. As that delta increases (from heat being removed from the air blowing over the hull), the firebox wants to replace that heat. The bigger the delta, the harder it will work to equalize it. This is a VERY hard thing to understand, grasp and visualize. It took me a month with a physicist to understand or grasp the same theory about the hot water freezing before the cold water when put in the freezer. There is not more energy (BTU) released or moved in the water, it is just released or moved faster. Same will go for the fire box, and in order to release it, it has to burn/create it.

 

I do ALOT of things, I tell people not to do!