In loving memory of Kenis D. Keathley 6/4/81 - 3/27/22 Loving father, husband, brother, friend and firewood hoarder Rest in peace, Dexterday

Face cord v cord

Discussion in 'The Wood Pile' started by Grahamt, Sep 7, 2018.

  1. Grahamt

    Grahamt

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    Iv read the difference a thousand times in hear , I don’t have room to stack accurately and measure what I have.
    How about a few pics of each just so I can compare in my head .
    Cheers
     
  2. In the Pines

    In the Pines

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  3. Grahamt

    Grahamt

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    That’s perfect thanks .
    It’s the death of the stack that’s the difference
     
  4. SkidderDone

    SkidderDone

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    To properly assess my stacks I've gone to counting ricks (8' long, 4' high, in 16" splits). I like it because it's more modular. I cut all my splits to 16" and I put my wood on pallets so I know that 2 pallets long is about 2 ricks as long as the stacks are 4' high. 3 ricks = a full cord (American). Now all I have to do is count the pallets and I know how much wood I have.
     
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  5. campinspecter

    campinspecter

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    Length 68 feet May 30 2018 (4).JPG
    Average height 6 feet
    May 30 2018 (3).JPG
    Average split 22 inch in length
    May 30 2018 (5).JPG
    68'x 6' x 22"= 5.8 cords
     
  6. Grahamt

    Grahamt

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  7. Sean

    Sean

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    I would just pull out your tape measure and find a cord calculator on your computer. Easy as can be. You dont even need to do the math. Just plug in your measurements and off you go!
     
  8. billb3

    billb3

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    From the menu bar if you go to the resources page you can end up at the site's cordwood calculator:
    Firewood & Cord Calcuations


    you don't even have to convert 14 inches into 1.1666 feet, it will do that for you.

    it's still nice to put a number on heating resources you've used for the year even if it's a rough number.


    it can't be all that much harder than tallying bottled spirits. :)
     
  9. Mwalsh9152

    Mwalsh9152

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    All of my wood is calculated by single rows. I fill an area with as much as I can fit. I am currently filling an area where each row is .7 of a cord. Then just multiply from there.